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Bihar Board Class 11 Science Physics · Ch 2: Motion in a Straight Line

Bihar Board Class 11 Science Physics · Ch 2: Motion in a Straight Line is an online chapter test in the Bihar Board Class 11 Science pattern, covering Motion in a Straight Line. Attempt it on SeatBeat with a timer like the real exam, then see a detailed solution for every question and your score and weak-topic analysis.

30
Questions
20
Minutes
30
Marks
None
Negative marking
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Topics in this test

TopicQuestions
Motion in a Straight Line30

Difficulty: 7 medium · 23 hard

Motion in a Straight Line MCQ questions with answers

The first 3 of 30 questions. Unlock the series for the rest, each with a solution.

  1. Q1. A car moving at $72\ \text{km/h}$ is brought to rest by applying brakes, and it stops in $4\ \text{s}$. Assuming uniform retardation, what distance does the car travel before stopping?

    $72\ \text{km/h}$ की चाल से चल रही एक कार को ब्रेक लगाकर विराम में लाया जाता है, और यह $4\ \text{s}$ में रुक जाती है। समान मंदन मानते हुए, रुकने से पहले कार कितनी दूरी तय करती है?

    • A. $144\ \text{m}$
    • B. $80\ \text{m}$
    • C. $20\ \text{m}$
    • D. $40\ \text{m}$
    Solution

    First convert: $72\ \text{km/h} = 20\ \text{m/s}$. Retardation $a = \frac{20}{4} = 5\ \text{m/s}^2$, so distance $= \frac{v^2}{2a} = \frac{400}{10} = 40\ \text{m}$. Forgetting the km/h to m/s conversion leads to the wrong answers.

    पहले परिवर्तित करें: $72\ \text{km/h} = 20\ \text{m/s}$। मंदन $a = \frac{20}{4} = 5\ \text{m/s}^2$, इसलिए दूरी $= \frac{v^2}{2a} = \frac{400}{10} = 40\ \text{m}$। km/h से m/s में परिवर्तन भूल जाने पर गलत उत्तर मिलते हैं।

  2. Q2. A stone is thrown vertically upward with an initial speed of $20\ \text{m/s}$. Taking $g = 10\ \text{m/s}^2$ and neglecting air resistance, what is the maximum height reached by the stone?

    एक पत्थर को $20\ \text{m/s}$ के प्रारंभिक चाल से ऊर्ध्वाधर ऊपर की ओर फेंका जाता है। $g = 10\ \text{m/s}^2$ लेते हुए और वायु प्रतिरोध को नगण्य मानते हुए, पत्थर द्वारा प्राप्त अधिकतम ऊँचाई क्या है?

    • A. $2\ \text{m}$
    • B. $10\ \text{m}$
    • C. $20\ \text{m}$
    • D. $40\ \text{m}$
    Solution

    At maximum height the final velocity is zero, so $h = \frac{u^2}{2g} = \frac{20^2}{2\times10} = 20\ \text{m}$. Using $u^2/g$ or $ut$ without the factor $2g$ gives the common wrong answers.

    अधिकतम ऊँचाई पर अंतिम वेग शून्य होता है, इसलिए $h = \frac{u^2}{2g} = \frac{20^2}{2\times10} = 20\ \text{m}$। $2g$ के गुणक के बिना $u^2/g$ या $ut$ का उपयोग करने पर सामान्य गलत उत्तर मिलते हैं।

  3. Q3. Which of the following correctly matches a feature of a motion graph with the physical quantity it represents?

    निम्नलिखित में से कौन-सा गति ग्राफ की किसी विशेषता को उस भौतिक राशि से सही ढंग से मिलाता है जिसे वह निरूपित करती है?

    • A. Area under velocity–time graph → velocity / वेग–समय ग्राफ के नीचे का क्षेत्रफल → वेग
    • B. Slope of velocity–time graph → acceleration / वेग–समय ग्राफ की ढलान → त्वरण
    • C. Slope of velocity–time graph → displacement / वेग–समय ग्राफ की ढलान → विस्थापन
    • D. Slope of position–time graph → acceleration / स्थिति–समय ग्राफ की ढलान → त्वरण
    Solution

    The slope of a velocity–time graph gives acceleration. The slope of a position–time graph gives velocity (not acceleration), and the area under a velocity–time graph gives displacement.

    वेग–समय ग्राफ की ढलान त्वरण देती है। स्थिति–समय ग्राफ की ढलान वेग (त्वरण नहीं) देती है, और वेग–समय ग्राफ के नीचे का क्षेत्रफल विस्थापन देता है।

Frequently asked questions

How many questions are in the Bihar Board Class 11 Science Physics · Ch 2: Motion in a Straight Line?

30 questions for 30 marks, to be answered in 20 minutes.

Is there negative marking in the Bihar Board Class 11 Science Physics · Ch 2: Motion in a Straight Line?

No — wrong answers are not penalised in this test.

Which topics does the Bihar Board Class 11 Science Physics · Ch 2: Motion in a Straight Line cover?

Motion in a Straight Line (30 questions).

Is the Bihar Board Class 11 Science Physics · Ch 2: Motion in a Straight Line free?

It is part of the BSEB Class 11 Science Test Series 2027 — Chapter-wise + Full Tests (20 tests, ₹149). You can first try Biology · Ch 1: The Living World for free.

More tests in the BSEB Class 11 Science Test Series 2027 — Chapter-wise + Full Tests

See the full BSEB Class 11 Science Test Series 2027 — Chapter-wise + Full Tests → · Bihar Board Class 11 Science: pattern, notification & syllabus →

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Motion in a Straight Line MCQ Questions with Answers | Bihar Board Class 11 | SeatBeat