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Bihar Board Class 9 Mathematics · Ch 2: Introduction to Linear Polynomials

Bihar Board Class 9 Mathematics · Ch 2: Introduction to Linear Polynomials is an online chapter test in the Bihar Board Class 9 pattern, covering Introduction to Linear Polynomials. Attempt it on SeatBeat with a timer like the real exam, then see a detailed solution for every question and your score and weak-topic analysis.

30
Questions
20
Minutes
30
Marks
None
Negative marking
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Topics in this test

TopicQuestions
Introduction to Linear Polynomials30

Difficulty: 7 medium · 23 hard

Introduction to Linear Polynomials MCQ questions with answers

The first 3 of 30 questions. Unlock the series for the rest, each with a solution.

  1. Q1. Odd one out: which of these is NOT a polynomial in one variable?

    भिन्न चुनिए: इनमें से कौन-सा एक चर वाला बहुपद नहीं है?

    • A. $\sqrt{2}\, x + 4$
    • B. $x^3 + 7$
    • C. $x + \frac{1}{x}$
    • D. $3x^2 - 5x + 2$
    Solution

    A polynomial cannot have a variable in the denominator (a negative power), so $x + \frac{1}{x}$ is not a polynomial.

    किसी बहुपद में चर हर में (ऋणात्मक घात) नहीं हो सकता, अतः $x + \frac{1}{x}$ एक बहुपद नहीं है।

  2. Q2. Factorise: $x^3 - 8$. Which of the following is correct?

    गुणनखंड कीजिए: $x^3 - 8$। निम्नलिखित में से कौन-सा सही है?

    • A. $(x - 2)(x^2 + 2x + 4)$
    • B. $(x + 2)(x^2 - 2x + 4)$
    • C. $(x - 2)(x^2 + 2x - 4)$
    • D. $(x - 2)(x^2 - 2x + 4)$
    Solution

    Using $a^3 - b^3 = (a-b)(a^2+ab+b^2)$ with $b = 2$ gives $(x-2)(x^2+2x+4)$.

    $a^3 - b^3 = (a-b)(a^2+ab+b^2)$ में $b = 2$ का प्रयोग करने पर $(x-2)(x^2+2x+4)$ प्राप्त होता है।

  3. Q3. Assertion (A): $x = \frac{3}{2}$ is a zero of the polynomial $p(x) = 2x - 3$. Reason (R): A zero of a polynomial $p(x)$ is a value of $x$ for which $p(x) = 0$. Choose the correct option:

    अभिकथन (A): $x = \frac{3}{2}$ बहुपद $p(x) = 2x - 3$ का एक शून्यक है। कारण (R): किसी बहुपद $p(x)$ का शून्यक $x$ का वह मान होता है जिसके लिए $p(x) = 0$ होता है। सही विकल्प चुनिए:

    • A. A is true but R is false / A सत्य है परंतु R असत्य है
    • B. Both A and R are true and R is the correct explanation of A / A और R दोनों सत्य हैं तथा R, A की सही व्याख्या है
    • C. Both A and R are true but R is not the correct explanation of A / A और R दोनों सत्य हैं परंतु R, A की सही व्याख्या नहीं है
    • D. A is false but R is true / A असत्य है परंतु R सत्य है
    Solution

    Putting $x = \frac{3}{2}$ gives $2 \times \frac{3}{2} - 3 = 0$, so A is true, and R correctly defines a zero and explains A.

    $x = \frac{3}{2}$ रखने पर $2 \times \frac{3}{2} - 3 = 0$ प्राप्त होता है, अतः A सत्य है, और R शून्यक को सही परिभाषित करता है तथा A की व्याख्या करता है।

Frequently asked questions

How many questions are in the Bihar Board Class 9 Mathematics · Ch 2: Introduction to Linear Polynomials?

30 questions for 30 marks, to be answered in 20 minutes.

Is there negative marking in the Bihar Board Class 9 Mathematics · Ch 2: Introduction to Linear Polynomials?

No — wrong answers are not penalised in this test.

Which topics does the Bihar Board Class 9 Mathematics · Ch 2: Introduction to Linear Polynomials cover?

Introduction to Linear Polynomials (30 questions).

Is the Bihar Board Class 9 Mathematics · Ch 2: Introduction to Linear Polynomials free?

It is part of the BSEB Class 9 Test Series 2027 — Chapter-wise + Full Tests (20 tests, ₹99). You can first try English · Ch 1: Dharam Juddha for free.

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Introduction to Linear Polynomials MCQ Questions with Answers | Bihar Board Class 9 | SeatBeat