Assertion (A): In uniform circular motion the speed of the particle is constant but its velocity changes continuously. Reason (R): The direction of motion of the particle changes continuously. Choose the correct option.

Both A and R are true, and R is the correct explanation of A

Both A and R are true, but R is not the correct explanation of A

Chapter testPhysicsIncluded in the seriesTest 18 of 36

Bihar Board Class 11 Science Physics · Ch 3: Motion in a Plane

Bihar Board Class 11 Science Physics · Ch 3: Motion in a Plane is an online chapter test in the Bihar Board Class 11 Science pattern, covering Motion in a Plane. Attempt it on SeatBeat with a timer like the real exam, then see a detailed solution for every question and your score and weak-topic analysis.

Questions

Minutes

Marks

None

Negative marking

Unlock all 36 tests — ₹149 Try Biology · Ch 1: The Living World free →

Topics in this test

Topic	Subject	Questions
Motion in a Plane	Physics	30

Difficulty: 7 medium · 23 hard

Motion in a Plane MCQ questions with answers

The first 3 of 30 questions. Unlock the series for the rest, each with a solution.

Q1. Consider the following statements about the resultant of two vectors: (i) Its magnitude can never be greater than the sum of the two magnitudes. (ii) Its magnitude can be less than the magnitude of either vector. (iii) The resultant of two vectors of unequal magnitude can be zero. Which statements are correct?
दो सदिशों के परिणामी के बारे में निम्नलिखित कथनों पर विचार कीजिए: (i) इसका परिमाण कभी भी दोनों परिमाणों के योग से अधिक नहीं हो सकता। (ii) इसका परिमाण किसी भी एक सदिश के परिमाण से कम हो सकता है। (iii) असमान परिमाण के दो सदिशों का परिणामी शून्य हो सकता है। कौन-से कथन सही हैं?
- A. (i) only / केवल (i)
- B. (i) and (ii) only / केवल (i) और (ii)
- C. (ii) and (iii) only / केवल (ii) और (iii)
- D. (i), (ii) and (iii) / (i), (ii) और (iii)
Solution
The resultant lies between $|A-B|$ and $A+B$, so (i) and (ii) are correct; two unequal vectors can never cancel completely, so (iii) is wrong.
परिणामी $|A-B|$ और $A+B$ के बीच होता है, अतः (i) और (ii) सही हैं; दो असमान सदिश कभी भी पूर्णतः एक-दूसरे को निरस्त नहीं कर सकते, अतः (iii) गलत है।
Q2. Match the quantity in Column I with its formula in Column II for a projectile launched with speed $u$ at angle $\theta$: Column I: (P) Time of flight (Q) Maximum height (R) Horizontal range Column II: (1) $\frac{u^2\sin^2\theta}{2g}$ (2) $\frac{2u\sin\theta}{g}$ (3) $\frac{u^2\sin 2\theta}{g}$
कॉलम I की राशि को चाल $u$ से कोण $\theta$ पर प्रक्षेपित किए गए प्रक्षेप्य के लिए कॉलम II में इसके सूत्र से सुमेलित कीजिए: कॉलम I: (P) उड्डयन काल (Q) अधिकतम ऊँचाई (R) क्षैतिज परास कॉलम II: (1) $\frac{u^2\sin^2\theta}{2g}$ (2) $\frac{2u\sin\theta}{g}$ (3) $\frac{u^2\sin 2\theta}{g}$
- A. P-3, Q-1, R-2
- B. P-2, Q-3, R-1
- C. P-1, Q-2, R-3
- D. P-2, Q-1, R-3
Solution
Time of flight is $\frac{2u\sin\theta}{g}$, maximum height is $\frac{u^2\sin^2\theta}{2g}$, and range is $\frac{u^2\sin 2\theta}{g}$, giving P-2, Q-1, R-3.
उड्डयन काल $\frac{2u\sin\theta}{g}$ है, अधिकतम ऊँचाई $\frac{u^2\sin^2\theta}{2g}$ है, और परास $\frac{u^2\sin 2\theta}{g}$ है, जिससे P-2, Q-1, R-3 प्राप्त होता है।
Q3. Assertion (A): In uniform circular motion the speed of the particle is constant but its velocity changes continuously. Reason (R): The direction of motion of the particle changes continuously. Choose the correct option.
अभिकथन (A): एकसमान वृत्तीय गति में कण की चाल नियत रहती है परन्तु इसका वेग निरंतर बदलता रहता है। कारण (R): कण की गति की दिशा निरंतर बदलती रहती है। सही विकल्प चुनिए।
- A. Both A and R are true, but R is not the correct explanation of A / A और R दोनों सत्य हैं, परन्तु R, A की सही व्याख्या नहीं है
- B. A is false but R is true / A असत्य है परन्तु R सत्य है
- C. Both A and R are true, and R is the correct explanation of A / A और R दोनों सत्य हैं, और R, A की सही व्याख्या है
- D. A is true but R is false / A सत्य है परन्तु R असत्य है
Solution
Velocity is a vector, so even with constant speed, the continuous change in direction means the velocity keeps changing. R correctly explains A.
वेग एक सदिश है, अतः नियत चाल के बावजूद, दिशा में निरंतर परिवर्तन का अर्थ है कि वेग बदलता रहता है। R, A की सही व्याख्या करता है।

Frequently asked questions

How many questions are in the Bihar Board Class 11 Science Physics · Ch 3: Motion in a Plane?

30 questions for 30 marks, to be answered in 20 minutes.

Is there negative marking in the Bihar Board Class 11 Science Physics · Ch 3: Motion in a Plane?

No — wrong answers are not penalised in this test.

Which topics does the Bihar Board Class 11 Science Physics · Ch 3: Motion in a Plane cover?

Motion in a Plane (30 questions).

Is the Bihar Board Class 11 Science Physics · Ch 3: Motion in a Plane free?

It is part of the BSEB Class 11 Science Test Series 2027 — Chapter-wise + Full Tests (36 tests, ₹149). You can first try Biology · Ch 1: The Living World for free.

More tests in the BSEB Class 11 Science Test Series 2027 — Chapter-wise + Full Tests

See the full BSEB Class 11 Science Test Series 2027 — Chapter-wise + Full Tests → · Bihar Board Class 11 Science: pattern, notification & syllabus →

₹149

View the full series