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Bihar Board Class 12 Science Physics · Ch 3: Current Electricity

Bihar Board Class 12 Science Physics · Ch 3: Current Electricity is an online chapter test in the Bihar Board Class 12 Science pattern, covering Current Electricity. Attempt it on SeatBeat with a timer like the real exam, then see a detailed solution for every question and your score and weak-topic analysis.

30
Questions
20
Minutes
30
Marks
None
Negative marking
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Topics in this test

TopicQuestions
Current Electricity30

Difficulty: 7 medium · 23 hard

Current Electricity MCQ questions with answers

The first 3 of 30 questions. Unlock the series for the rest, each with a solution.

  1. Q1. The temperature coefficient of resistance of a conductor is $0.004\,^\circ\text{C}^{-1}$. If its resistance at $0\,^\circ\text{C}$ is $50\,\Omega$, the temperature at which its resistance becomes $60\,\Omega$ is:

    किसी चालक के प्रतिरोध का तापमान गुणांक $0.004\,^\circ\text{C}^{-1}$ है। यदि $0\,^\circ\text{C}$ पर इसका प्रतिरोध $50\,\Omega$ है, तो वह तापमान जिस पर इसका प्रतिरोध $60\,\Omega$ हो जाता है, है:

    • A. $50\,^\circ\text{C}$
    • B. $40\,^\circ\text{C}$
    • C. $25\,^\circ\text{C}$
    • D. $60\,^\circ\text{C}$
    Solution

    Using $R_T=R_0(1+\alpha T)$, $60=50(1+0.004\,T)$ gives $1.2=1+0.004\,T$, so $T=\dfrac{0.2}{0.004}=50\,^\circ\text{C}$.

    $R_T=R_0(1+\alpha T)$ का उपयोग करने पर, $60=50(1+0.004\,T)$ से $1.2=1+0.004\,T$, अतः $T=\dfrac{0.2}{0.004}=50\,^\circ\text{C}$।

  2. Q2. Match the quantity in List I with its correct expression in List II. List I: (P) Drift velocity, (Q) Current density, (R) Mobility, (S) Conductivity. List II: (1) $ne^2\tau/m$, (2) $e\tau/m$, (3) $I/A$, (4) $eE\tau/m$. The correct matching is:

    सूची I में दी गई राशि का सूची II में उसके सही व्यंजक से मिलान कीजिए। सूची I: (P) अनुगमन वेग, (Q) धारा घनत्व, (R) गतिशीलता (mobility), (S) चालकता। सूची II: (1) $ne^2\tau/m$, (2) $e\tau/m$, (3) $I/A$, (4) $eE\tau/m$। सही मिलान है:

    • A. P-1, Q-3, R-2, S-4
    • B. P-2, Q-3, R-4, S-1
    • C. P-4, Q-3, R-2, S-1
    • D. P-4, Q-1, R-2, S-3
    Solution

    Drift velocity $=eE\tau/m$, current density $=I/A$, mobility $=e\tau/m$ and conductivity $=ne^2\tau/m$. So P-4, Q-3, R-2, S-1.

    अनुगमन वेग $=eE\tau/m$, धारा घनत्व $=I/A$, गतिशीलता $=e\tau/m$ तथा चालकता $=ne^2\tau/m$। अतः P-4, Q-3, R-2, S-1।

  3. Q3. Three identical cells, each of emf $2\,\text{V}$ and internal resistance $0.2\,\Omega$, are connected in series across an external resistance of $5.4\,\Omega$. The current drawn from the combination is:

    तीन समान सेल, प्रत्येक $2\,\text{V}$ emf तथा $0.2\,\Omega$ आंतरिक प्रतिरोध वाले, $5.4\,\Omega$ के बाह्य प्रतिरोध पर श्रेणीक्रम में जोड़े गए हैं। संयोजन से ली गई धारा है:

    • A. $1\,\text{A}$
    • B. $1.1\,\text{A}$
    • C. $3\,\text{A}$
    • D. $0.33\,\text{A}$
    Solution

    In series, total emf $=6\,\text{V}$ and total internal resistance $=0.6\,\Omega$, so $I=\dfrac{6}{5.4+0.6}=\dfrac{6}{6}=1\,\text{A}$.

    श्रेणीक्रम में, कुल emf $=6\,\text{V}$ तथा कुल आंतरिक प्रतिरोध $=0.6\,\Omega$, अतः $I=\dfrac{6}{5.4+0.6}=\dfrac{6}{6}=1\,\text{A}$।

Frequently asked questions

How many questions are in the Bihar Board Class 12 Science Physics · Ch 3: Current Electricity?

30 questions for 30 marks, to be answered in 20 minutes.

Is there negative marking in the Bihar Board Class 12 Science Physics · Ch 3: Current Electricity?

No — wrong answers are not penalised in this test.

Which topics does the Bihar Board Class 12 Science Physics · Ch 3: Current Electricity cover?

Current Electricity (30 questions).

Is the Bihar Board Class 12 Science Physics · Ch 3: Current Electricity free?

It is part of the BSEB Class 12 Science Test Series 2027 — Chapter-wise + Full Tests (27 tests, ₹149). You can first try Hindi · Ch 1: Chandradhar Sharma Guleri for free.

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Current Electricity MCQ Questions with Answers | Bihar Board Class 12 (Inter) | SeatBeat