A scooter covers 10 m in the first 2 s, 10 m in the next 2 s, and 10 m in the following 2 s of its journey. What type of motion is this, and why?

Uniform motion, because equal distances are covered in equal intervals of time

Non-uniform motion, because the speed keeps increasing every 2 seconds

Non-uniform motion, because the scooter must be accelerating to keep each interval equal

Uniform motion, because the distance covered is proportional to the square of time

Which one of the following equations of motion for uniformly accelerated motion is written incorrectly?

$s = \left(\frac{u+v}{2}\right)t$

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Bihar Board Class 9 Science · Ch 3: Describing Motion Around Us

Bihar Board Class 9 Science · Ch 3: Describing Motion Around Us is an online chapter test in the Bihar Board Class 9 pattern, covering Describing Motion Around Us. Attempt it on SeatBeat with a timer like the real exam, then see a detailed solution for every question and your score and weak-topic analysis.

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Topics in this test

Topic	Subject	Questions
Describing Motion Around Us	Science	30

Difficulty: 7 medium · 23 hard

Describing Motion Around Us MCQ questions with answers

The first 3 of 30 questions. Unlock the series for the rest, each with a solution.

Q1. A scooter covers 10 m in the first 2 s, 10 m in the next 2 s, and 10 m in the following 2 s of its journey. What type of motion is this, and why?
अपनी यात्रा के पहले 2 सेकंड में एक स्कूटर 10 मीटर, अगले 2 सेकंड में 10 मीटर, और उसके बाद के 2 सेकंड में 10 मीटर तय करता है। यह किस प्रकार की गति है, और क्यों?
- A. Non-uniform motion, because the speed keeps increasing every 2 seconds / असमान गति, क्योंकि चाल प्रत्येक 2 सेकंड में बढ़ती रहती है
- B. Non-uniform motion, because the scooter must be accelerating to keep each interval equal / असमान गति, क्योंकि प्रत्येक अंतराल को समान रखने के लिए स्कूटर का त्वरित होना आवश्यक है
- C. Uniform motion, because the distance covered is proportional to the square of time / एकसमान गति, क्योंकि तय की गई दूरी समय के वर्ग के अनुक्रमानुपाती है
- D. Uniform motion, because equal distances are covered in equal intervals of time / एकसमान गति, क्योंकि समान समय अंतरालों में समान दूरियाँ तय की जाती हैं
Solution
Since the scooter covers equal distances (10 m) in each equal interval of time (2 s), its speed is not changing, so the motion is uniform, not accelerated.
चूँकि स्कूटर प्रत्येक समान समय अंतराल (2 सेकंड) में समान दूरी (10 मीटर) तय करता है, इसलिए उसकी चाल नहीं बदल रही है, अतः यह गति एकसमान है, त्वरित नहीं।
Q2. A car moving with a velocity of $20\,m/s$ is uniformly retarded and comes to rest in $5\,s$. What distance does the car travel before stopping?
$20\,m/s$ के वेग से गतिमान एक कार एकसमान रूप से मंदित होती है और $5\,s$ में विराम में आ जाती है। विराम में आने से पहले कार कितनी दूरी तय करती है?
- A. 100 m / 100 मीटर
- B. 50 m / 50 मीटर
- C. 4 m / 4 मीटर
- D. 20 m / 20 मीटर
Solution
Using $v^2 = u^2 + 2as$ with $v=0$, $u=20$, we get the retardation $a = -4\,m/s^2$, and then $s = ut + \frac{1}{2}at^2 = 100 - 50 = 50$ m.
$v^2 = u^2 + 2as$ का उपयोग करते हुए, जहाँ $v=0$, $u=20$ है, हमें मंदन $a = -4\,m/s^2$ प्राप्त होता है, और फिर $s = ut + \frac{1}{2}at^2 = 100 - 50 = 50$ मीटर।
Q3. Which one of the following equations of motion for uniformly accelerated motion is written incorrectly?
एकसमान त्वरित गति के लिए निम्नलिखित गति के समीकरणों में से कौन सा गलत लिखा गया है?
- A. $s = ut + \frac{1}{2}at^2$
- B. $s = \left(\frac{u+v}{2}\right)t$
- C. $v = u + at$
- D. $v^2 = u^2 - 2as$
Solution
The correct third equation of motion is $v^2 = u^2 + 2as$ with a plus sign, not a minus sign, so option showing $v^2 = u^2 - 2as$ is wrong.
गति का सही तीसरा समीकरण $v^2 = u^2 + 2as$ है जिसमें धन चिह्न होता है, ऋण चिह्न नहीं, इसलिए $v^2 = u^2 - 2as$ दिखाने वाला विकल्प गलत है।

Frequently asked questions

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30 questions for 30 marks, to be answered in 20 minutes.

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No — wrong answers are not penalised in this test.

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Describing Motion Around Us (30 questions).

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It is part of the BSEB Class 9 Test Series 2027 — Chapter-wise + Full Tests (36 tests, ₹99). You can first try English · Ch 1: Dharam Juddha for free.

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