JEE Main Inorganic — p/d/f Block & Coordination: Coordination Compounds – Chapter Test

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Difficulty: 10 medium · 10 hard

Coordination Compounds MCQ questions with answers

The first 3 of 20 questions. Unlock the series for the rest, each with a solution.

1. Q1. Which of the following ions is colourless (does not show absorption of visible light by d–d transitions)?

   निम्नलिखित में से कौन-सा आयन रंगहीन है (d–d संक्रमणों द्वारा दृश्य प्रकाश का अवशोषण नहीं दर्शाता)?

   • A. [Zn(NH₃)₄]²⁺
   • B. [Ni(H₂O)₆]²⁺
   • C. [Cu(NH₃)₄]²⁺
   • D. [Ti(H₂O)₆]³⁺
   Solution

   Zn²⁺ has a completely filled 3d¹⁰ configuration, so no d–d transition is possible and [Zn(NH₃)₄]²⁺ is colourless. [Cu(NH₃)₄]²⁺ (d⁹), [Ni(H₂O)₆]²⁺ (d⁸) and [Ti(H₂O)₆]³⁺ (d¹) all undergo d–d transitions and are coloured.

   Zn²⁺ में पूर्णतः भरा हुआ 3d¹⁰ विन्यास है, अतः कोई d–d संक्रमण संभव नहीं है और [Zn(NH₃)₄]²⁺ रंगहीन है। [Cu(NH₃)₄]²⁺ (d⁹), [Ni(H₂O)₆]²⁺ (d⁸) और [Ti(H₂O)₆]³⁺ (d¹) सभी d–d संक्रमण करते हैं और रंगीन होते हैं।

2. Q2. The spin-only magnetic moment (in BM) of the complex ion [Ni(CN)₄]²⁻ is closest to:

   संकुल आयन [Ni(CN)₄]²⁻ का चक्रण-मात्र चुंबकीय आघूर्ण (BM में) सबसे निकट है:

   • A. 3.87
   • B. 2.83
   • C. 0
   • D. 1.73
   Solution

   Ni²⁺ is d⁸; the strong-field CN⁻ ligand produces a square planar, low-spin arrangement with all eight electrons paired, so the complex is diamagnetic with a moment of 0 BM.

   Ni²⁺ d⁸ है; प्रबल-क्षेत्र CN⁻ लिगैंड एक वर्ग समतलीय, निम्न-चक्रण व्यवस्था उत्पन्न करता है जिसमें सभी आठ इलेक्ट्रॉन युग्मित होते हैं, अतः संकुल प्रतिचुंबकीय है और इसका आघूर्ण 0 BM है।

3. Q3. The spin-only magnetic moment (in BM) of [Cr(H₂O)₆]³⁺ is closest to:

   [Cr(H₂O)₆]³⁺ का चक्रण-मात्र चुंबकीय आघूर्ण (BM में) सबसे निकट है:

   • A. 1.73
   • B. 2.83
   • C. 4.90
   • D. 3.87
   Solution

   Cr³⁺ is a d³ ion; the three electrons occupy the three t₂g orbitals singly, giving three unpaired electrons and μ = √(3×5) = 3.87 BM.

   Cr³⁺ एक d³ आयन है; तीनों इलेक्ट्रॉन तीन t₂g कक्षकों में एकल रूप से रहते हैं, जिससे तीन अयुग्मित इलेक्ट्रॉन और μ = √(3×5) = 3.87 BM मिलता है।

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