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JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test

JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test is an online chapter test in the JEE Main pattern, covering Physical Chemistry — Electrochemistry & Kinetics. Attempt it on SeatBeat with a timer like the real exam, then see a detailed solution for every question and your score and weak-topic analysis.

20
Questions
20
Minutes
20
Marks
−0.25
Negative marking

Topics in this test

TopicQuestions
Physical Chemistry — Electrochemistry & Kinetics20

Difficulty: 10 medium · 10 hard

Redox Reactions and Electrochemistry MCQ questions with answers

The first 3 of 20 questions. Unlock the series for the rest, each with a solution.

  1. Q1. Given the standard reduction potentials E°(MnO4⁻/Mn²⁺) = +1.51 V, E°(Cr2O7²⁻/Cr³⁺) = +1.33 V, E°(Cl2/Cl⁻) = +1.36 V and E°(Fe³⁺/Fe²⁺) = +0.77 V, the strongest oxidising agent among these species is:

    दिए गए मानक अपचयन विभव E°(MnO4⁻/Mn²⁺) = +1.51 V, E°(Cr2O7²⁻/Cr³⁺) = +1.33 V, E°(Cl2/Cl⁻) = +1.36 V तथा E°(Fe³⁺/Fe²⁺) = +0.77 V के आधार पर, इन स्पीशीज़ में सबसे प्रबल ऑक्सीकारक है:

    • A. Cr2O7²⁻
    • B. Fe³⁺
    • C. Cl2
    • D. MnO4⁻
    Solution

    A larger (more positive) standard reduction potential means a stronger oxidising agent. MnO4⁻ has the highest value (+1.51 V), so it is the strongest oxidising agent.

    अधिक (अधिक धनात्मक) मानक अपचयन विभव का अर्थ है अधिक प्रबल ऑक्सीकारक। MnO4⁻ का मान सर्वाधिक (+1.51 V) है, अतः यह सबसे प्रबल ऑक्सीकारक है।

  2. Q2. For a weak monobasic acid, the limiting molar conductivity is Λ°m = 400 S cm² mol⁻¹ and the molar conductivity at a given concentration is Λm = 20 S cm² mol⁻¹. The degree of dissociation of the acid at this concentration is:

    किसी दुर्बल एकक्षारकीय अम्ल के लिए, सीमांत मोलर चालकता Λ°m = 400 S cm² mol⁻¹ तथा किसी दी गई सांद्रता पर मोलर चालकता Λm = 20 S cm² mol⁻¹ है। इस सांद्रता पर अम्ल की वियोजन मात्रा (डिग्री ऑफ़ डिसोसिएशन) है:

    • A. 0.025
    • B. 0.05
    • C. 0.20
    • D. 0.50
    Solution

    For a weak electrolyte, α = Λm / Λ°m = 20/400 = 0.05, i.e. 5% dissociation.

    किसी दुर्बल विद्युत अपघट्य के लिए, α = Λm / Λ°m = 20/400 = 0.05, अर्थात् 5% वियोजन।

  3. Q3. The value of the Faraday constant, representing the charge carried by one mole of electrons, is closest to:

    फैराडे स्थिरांक का मान, जो एक मोल इलेक्ट्रॉनों द्वारा वहन किए गए आवेश को निरूपित करता है, निकटतम रूप से है:

    • A. 96485 C mol⁻¹
    • B. 6.022 × 10²³ C mol⁻¹
    • C. 1.602 × 10⁻¹⁹ C mol⁻¹
    • D. 9648.5 C mol⁻¹
    Solution

    The Faraday constant is the product of the Avogadro number and the elementary charge, equal to about 96485 C mol⁻¹ (commonly rounded to 96500 C mol⁻¹).

    फैराडे स्थिरांक, एवोगैड्रो संख्या तथा मूल आवेश का गुणनफल है, जो लगभग 96485 C mol⁻¹ के बराबर है (सामान्यतः 96500 C mol⁻¹ तक पूर्णांकित किया जाता है)।

Frequently asked questions

How many questions are in the JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test?

20 questions for 20 marks, to be answered in 20 minutes.

Is there negative marking in the JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test?

Yes — 0.25 marks are deducted for each wrong answer, as in the real exam pattern.

Which topics does the JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test cover?

Physical Chemistry — Electrochemistry & Kinetics (20 questions).

Is the JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test free?

It is part of the JEE Main 2027 Mock Test Series (104 tests, ₹299). You can first try Basic Concepts & Atomic Structure – Topic Test for free.

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Redox Reactions and Electrochemistry MCQ | JEE Main