JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test
JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test is an online chapter test in the JEE Main pattern, covering Physical Chemistry — Electrochemistry & Kinetics. Attempt it on SeatBeat with a timer like the real exam, then see a detailed solution for every question and your score and weak-topic analysis.
Topics in this test
| Topic | Questions |
|---|---|
| Physical Chemistry — Electrochemistry & Kinetics | 20 |
Difficulty: 10 medium · 10 hard
Redox Reactions and Electrochemistry MCQ questions with answers
The first 3 of 20 questions. Unlock the series for the rest, each with a solution.
Q1. Given the standard reduction potentials E°(MnO4⁻/Mn²⁺) = +1.51 V, E°(Cr2O7²⁻/Cr³⁺) = +1.33 V, E°(Cl2/Cl⁻) = +1.36 V and E°(Fe³⁺/Fe²⁺) = +0.77 V, the strongest oxidising agent among these species is:
दिए गए मानक अपचयन विभव E°(MnO4⁻/Mn²⁺) = +1.51 V, E°(Cr2O7²⁻/Cr³⁺) = +1.33 V, E°(Cl2/Cl⁻) = +1.36 V तथा E°(Fe³⁺/Fe²⁺) = +0.77 V के आधार पर, इन स्पीशीज़ में सबसे प्रबल ऑक्सीकारक है:
- A. Cr2O7²⁻
- B. Fe³⁺
- C. Cl2
- D. MnO4⁻
Solution
A larger (more positive) standard reduction potential means a stronger oxidising agent. MnO4⁻ has the highest value (+1.51 V), so it is the strongest oxidising agent.
अधिक (अधिक धनात्मक) मानक अपचयन विभव का अर्थ है अधिक प्रबल ऑक्सीकारक। MnO4⁻ का मान सर्वाधिक (+1.51 V) है, अतः यह सबसे प्रबल ऑक्सीकारक है।
Q2. For a weak monobasic acid, the limiting molar conductivity is Λ°m = 400 S cm² mol⁻¹ and the molar conductivity at a given concentration is Λm = 20 S cm² mol⁻¹. The degree of dissociation of the acid at this concentration is:
किसी दुर्बल एकक्षारकीय अम्ल के लिए, सीमांत मोलर चालकता Λ°m = 400 S cm² mol⁻¹ तथा किसी दी गई सांद्रता पर मोलर चालकता Λm = 20 S cm² mol⁻¹ है। इस सांद्रता पर अम्ल की वियोजन मात्रा (डिग्री ऑफ़ डिसोसिएशन) है:
- A. 0.025
- B. 0.05
- C. 0.20
- D. 0.50
Solution
For a weak electrolyte, α = Λm / Λ°m = 20/400 = 0.05, i.e. 5% dissociation.
किसी दुर्बल विद्युत अपघट्य के लिए, α = Λm / Λ°m = 20/400 = 0.05, अर्थात् 5% वियोजन।
Q3. The value of the Faraday constant, representing the charge carried by one mole of electrons, is closest to:
फैराडे स्थिरांक का मान, जो एक मोल इलेक्ट्रॉनों द्वारा वहन किए गए आवेश को निरूपित करता है, निकटतम रूप से है:
- A. 96485 C mol⁻¹
- B. 6.022 × 10²³ C mol⁻¹
- C. 1.602 × 10⁻¹⁹ C mol⁻¹
- D. 9648.5 C mol⁻¹
Solution
The Faraday constant is the product of the Avogadro number and the elementary charge, equal to about 96485 C mol⁻¹ (commonly rounded to 96500 C mol⁻¹).
फैराडे स्थिरांक, एवोगैड्रो संख्या तथा मूल आवेश का गुणनफल है, जो लगभग 96485 C mol⁻¹ के बराबर है (सामान्यतः 96500 C mol⁻¹ तक पूर्णांकित किया जाता है)।
Frequently asked questions
How many questions are in the JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test?
20 questions for 20 marks, to be answered in 20 minutes.
Is there negative marking in the JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test?
Yes — 0.25 marks are deducted for each wrong answer, as in the real exam pattern.
Which topics does the JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test cover?
Physical Chemistry — Electrochemistry & Kinetics (20 questions).
Is the JEE Main Physical Chemistry — Electrochemistry & Kinetics: Redox Reactions and Electrochemistry – Chapter Test free?
It is part of the JEE Main 2027 Mock Test Series (104 tests, ₹299). You can first try Basic Concepts & Atomic Structure – Topic Test for free.
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