NEET UG Magnetism, EMI & AC: Alternating Current – Chapter Test

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Difficulty: 7 medium · 13 hard

Alternating Current MCQ questions with answers

The first 3 of 20 questions. Unlock the series for the rest, each with a solution.

1. Q1. An ideal transformer has 200 turns in its primary and 1000 turns in its secondary. If 220 V (AC) is applied to the primary, the secondary voltage is:

   एक आदर्श ट्रांसफॉर्मर की प्राथमिक कुंडली में 200 फेरे और द्वितीयक कुंडली में 1000 फेरे हैं। यदि प्राथमिक कुंडली पर 220 V (AC) अनुप्रयुक्त किया जाए, तो द्वितीयक वोल्टता है:

   • A. 220 V
   • B. 44 V
   • C. 550 V
   • D. 1100 V
   Solution

   For an ideal transformer V_s/V_p = N_s/N_p, so V_s = 220 × (1000/200) = 220 × 5 = 1100 V (a step-up transformer).

   आदर्श ट्रांसफॉर्मर के लिए V_s/V_p = N_s/N_p, अतः V_s = 220 × (1000/200) = 220 × 5 = 1100 V (एक उच्चायी ट्रांसफॉर्मर)।

2. Q2. For a sinusoidal alternating current, the form factor (ratio of rms value to the average value taken over a half-cycle) is:

   एक ज्यावक्रीय प्रत्यावर्ती धारा के लिए, रूप गुणक (form factor) (rms मान और अर्ध-चक्र पर लिए गए औसत मान का अनुपात) है:

   • A. 1.41
   • B. 1.11
   • C. 0.637
   • D. 0.707
   Solution

   Form factor = (I0/√2)/(2I0/π) = π/(2√2) ≈ 1.11, a fixed number for a pure sine wave.

   रूप गुणक = (I0/√2)/(2I0/π) = π/(2√2) ≈ 1.11, जो शुद्ध ज्या तरंग के लिए एक निश्चित संख्या है।

3. Q3. An alternating voltage is given by V = 311 sin(314 t) volt, where t is in seconds. The root-mean-square value of this voltage is closest to:

   एक प्रत्यावर्ती वोल्टता V = 311 sin(314 t) वोल्ट द्वारा दी गई है, जहाँ t सेकंड में है। इस वोल्टता का वर्ग-माध्य-मूल (rms) मान सबसे निकट है:

   • A. 440 V
   • B. 220 V
   • C. 311 V
   • D. 156 V
   Solution

   For a sinusoid, V_rms = V_peak/√2 = 311/1.414 ≈ 220 V (standard Indian mains); the 314 rad/s corresponds to 50 Hz.

   ज्यावक्रीय (साइनसॉइडल) के लिए, V_rms = V_शिखर/√2 = 311/1.414 ≈ 220 V (मानक भारतीय मेन्स); 314 rad/s का मान 50 Hz के संगत है।

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