NEET UG Magnetism, EMI & AC: Electromagnetic Waves – Chapter Test
NEET UG Magnetism, EMI & AC: Electromagnetic Waves – Chapter Test is an online chapter test in the NEET UG pattern, covering Magnetism, EMI & AC. Attempt it on SeatBeat with a timer like the real exam, then see a detailed solution for every question and your score and weak-topic analysis.
Topics in this test
| Topic | Questions |
|---|---|
| Magnetism, EMI & AC | 20 |
Difficulty: 7 medium · 13 hard
Electromagnetic Waves MCQ questions with answers
The first 3 of 20 questions. Unlock the series for the rest, each with a solution.
Q1. The speed of electromagnetic waves in free space is expressed as:
मुक्त आकाश में विद्युतचुंबकीय तरंगों की चाल को व्यक्त किया जाता है:
- A. c = 1/(μ0ε0)
- B. c = √(μ0ε0)
- C. c = μ0ε0
- D. c = 1/√(μ0ε0)
Solution
From Maxwell's equations, the speed of EM waves in vacuum is c = 1/√(μ0ε0), which numerically equals about 3×10^8 m/s.
मैक्सवेल के समीकरणों से, निर्वात में विद्युतचुंबकीय तरंगों की चाल c = 1/√(μ0ε0) होती है, जो संख्यात्मक रूप से लगभग 3×10^8 m/s के बराबर है।
Q2. Among the following electromagnetic radiations, which one has the highest frequency?
निम्नलिखित विद्युतचुंबकीय विकिरणों में से किसकी आवृत्ति सर्वाधिक है?
- A. Gamma rays / गामा किरणें
- B. X-rays / एक्स-किरणें
- C. Ultraviolet / पराबैंगनी
- D. Microwaves / सूक्ष्मतरंगें
Solution
Gamma rays have the shortest wavelength and therefore the highest frequency of the listed radiations, followed by X-rays, ultraviolet and then microwaves.
गामा किरणों की तरंगदैर्घ्य सबसे कम होती है और इसलिए दी गई विकिरणों में इनकी आवृत्ति सर्वाधिक होती है, इसके बाद एक्स-किरणें, पराबैंगनी और फिर सूक्ष्मतरंगें आती हैं।
Q3. The speed of electromagnetic waves in free space is given by c = 1/√(μ0ε0). Using μ0 = 4π×10^-7 T·m·A^-1 and ε0 = 8.85×10^-12 C^2·N^-1·m^-2, the value of c is approximately:
मुक्त आकाश में विद्युतचुंबकीय तरंगों की चाल c = 1/√(μ0ε0) द्वारा दी जाती है। μ0 = 4π×10^-7 T·m·A^-1 और ε0 = 8.85×10^-12 C^2·N^-1·m^-2 का उपयोग करने पर, c का मान लगभग है:
- A. 3.0×10^9 m/s
- B. 9.0×10^16 m/s
- C. 1.1×10^8 m/s
- D. 3.0×10^8 m/s
Solution
μ0ε0 ≈ 1.11×10^-17, so √(μ0ε0) ≈ 3.33×10^-9 and c = 1/(3.33×10^-9) ≈ 3.0×10^8 m/s, matching the known speed of light.
μ0ε0 ≈ 1.11×10^-17, इसलिए √(μ0ε0) ≈ 3.33×10^-9 और c = 1/(3.33×10^-9) ≈ 3.0×10^8 m/s, जो प्रकाश की ज्ञात चाल से मेल खाता है।
Frequently asked questions
How many questions are in the NEET UG Magnetism, EMI & AC: Electromagnetic Waves – Chapter Test?
20 questions for 20 marks, to be answered in 20 minutes.
Is there negative marking in the NEET UG Magnetism, EMI & AC: Electromagnetic Waves – Chapter Test?
Yes — 0.25 marks are deducted for each wrong answer, as in the real exam pattern.
Which topics does the NEET UG Magnetism, EMI & AC: Electromagnetic Waves – Chapter Test cover?
Magnetism, EMI & AC (20 questions).
Is the NEET UG Magnetism, EMI & AC: Electromagnetic Waves – Chapter Test free?
It is part of the NEET UG 2027 Mock Test Series (134 tests, ₹299). You can first try Biology in Human Welfare – Topic Test for free.
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