NEET UG Thermodynamics & Equilibrium: Equilibrium – Chapter Test

Topics in this test

Difficulty: 10 medium · 10 hard

Equilibrium MCQ questions with answers

The first 3 of 20 questions. Unlock the series for the rest, each with a solution.

1. Q1. The pH of a 0.01 M aqueous solution of ammonia at 25 °C (Kb of NH3 = 1.8 × 10⁻⁵) is approximately:

   25 °C पर अमोनिया के 0.01 M जलीय विलयन का pH लगभग है (NH3 का Kb = 1.8 × 10⁻⁵):

   • A. 3.4
   • B. 10.6
   • C. 8.4
   • D. 11.6
   Solution

   [OH⁻] = √(Kb·C) = √(1.8 × 10⁻⁵ × 0.01) = √(1.8 × 10⁻⁷) ≈ 4.2 × 10⁻⁴ M, giving pOH ≈ 3.4 and pH = 14 − 3.4 ≈ 10.6.

   [OH⁻] = √(Kb·C) = √(1.8 × 10⁻⁵ × 0.01) = √(1.8 × 10⁻⁷) ≈ 4.2 × 10⁻⁴ M, जिससे pOH ≈ 3.4 और pH = 14 − 3.4 ≈ 10.6।

2. Q2. The molar solubility of a sparingly soluble salt of the type MX2 in water is 1.0 × 10⁻³ mol L⁻¹. Its solubility product Ksp is:

   जल में MX2 प्रकार के एक अल्प विलेय लवण की मोलर विलेयता 1.0 × 10⁻³ mol L⁻¹ है। इसका विलेयता गुणनफल Ksp है:

   • A. 1 × 10⁻⁹
   • B. 4 × 10⁻⁹
   • C. 2 × 10⁻⁶
   • D. 4 × 10⁻⁶
   Solution

   For MX2 dissolving to give one M²⁺ and two X⁻, Ksp = [M²⁺][X⁻]² = (s)(2s)² = 4s³ = 4 × (1.0 × 10⁻³)³ = 4 × 10⁻⁹.

   MX2 के घुलकर एक M²⁺ और दो X⁻ देने पर, Ksp = [M²⁺][X⁻]² = (s)(2s)² = 4s³ = 4 × (1.0 × 10⁻³)³ = 4 × 10⁻⁹।

3. Q3. Match List I (aqueous solution at 25 °C, assuming complete dissociation of the strong electrolytes) with List II (approximate pH). List I: A. 0.01 M HCl; B. 0.001 M NaOH; C. 0.05 M H2SO4; D. Pure water. List II: 1. pH 1; 2. pH 2; 3. pH 7; 4. pH 11. Select the correct matching:

   सूची I (25 °C पर जलीय विलयन, प्रबल विद्युत-अपघट्यों का पूर्ण वियोजन मानते हुए) को सूची II (लगभग pH) से सुमेलित कीजिए। सूची I: A. 0.01 M HCl; B. 0.001 M NaOH; C. 0.05 M H2SO4; D. शुद्ध जल। सूची II: 1. pH 1; 2. pH 2; 3. pH 7; 4. pH 11। सही सुमेलन चुनिए:

   • A. A-2, B-3, C-1, D-4
   • B. A-1, B-4, C-2, D-3
   • C. A-2, B-4, C-3, D-1
   • D. A-2, B-4, C-1, D-3
   Solution

   0.01 M HCl gives [H3O⁺] = 10⁻² M (pH 2); 0.001 M NaOH gives pOH 3, so pH 11; 0.05 M H2SO4 furnishes 2 × 0.05 = 0.1 M H3O⁺ (pH 1); pure water at 25 °C has pH 7. Hence A-2, B-4, C-1, D-3.

   0.01 M HCl से [H3O⁺] = 10⁻² M (pH 2) प्राप्त होता है; 0.001 M NaOH से pOH 3, अतः pH 11; 0.05 M H2SO4 से 2 × 0.05 = 0.1 M H3O⁺ (pH 1) प्राप्त होता है; 25 °C पर शुद्ध जल का pH 7 होता है। अतः A-2, B-4, C-1, D-3।

Frequently asked questions

More tests in the NEET UG 2027 Mock Test Series

• Biology in Human Welfare – Topic TestFree
• Cell Biology – Topic Test
• Diversity in the Living World – Topic Test
• Ecology – Topic Test
• Genetics – Topic Test
• Plant Physiology – Topic Test
• Plant Reproduction – Topic Test
• Structural Organisation in Plants – Topic Test
• Basic Concepts & Atomic Structure – Topic Test
• Biomolecules – Topic Test
• Inorganic: p/d/f Block & Coordination – Topic Test
• Organic: Basics & Hydrocarbons – Topic Test
• Organic: Functional Groups – Topic Test
• Periodicity & Chemical Bonding – Topic Test
• Solutions, Electrochemistry & Kinetics – Topic Test
• Thermodynamics & Equilibrium – Topic Test
• Electrostatics & Current Electricity – Topic Test
• Laws of Motion & Work-Energy – Topic Test
• Magnetism, EMI & AC – Topic Test
• Mechanics: Measurement & Kinematics – Topic Test
• Modern Physics & Electronics – Topic Test
• Optics – Topic Test
• Oscillations and Waves – Topic Test
• Properties of Matter & Heat – Topic Test
• Rotational Motion & Gravitation – Topic Test
• Animal Diversity – Topic Test
• Biomolecules & Cell Chemistry – Topic Test
• Biotechnology – Topic Test
• Evolution – Topic Test
• Human Physiology I: Nutrition, Respiration & Circulation – Topic Test

See the full NEET UG 2027 Mock Test Series → · NEET UG: pattern, notification & syllabus →